A car moving in the same direction passes a m | vedclass

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(B) Let the speed of the car be $x\, km/h$.The relative speed of the car with respect to the man is $(x - 4)\, km/h$.The man sees the car for $3\, min

Vedclass · Accepted Answer

$6 \frac{3}{5}$

Vedclass · Answer

(B) Let the speed of the car be $x\, km/h$.The relative speed of the car with respect to the man is $(x - 4)\, km/h$.The man sees the car for $3\, minutes$,which is $\frac{3}{60} = \frac{1}{20}\, hours$.The visibility distance is $130\, m$,which is $\frac{130}{1000} = 0.13\, km$.Using the formula: $	ext{Relative Speed} 	imes 	ext{Time} = 	ext{Distance}$$(x - 4) 	imes \frac{1}{20} = \frac{130}{1000}$$(x - 4) 	imes \frac{1}{20} = \frac{13}{100}$$x - 4 = \frac{13}{100} 	imes 20$$x - 4 = \frac{13}{5} = 2.6$$x = 2.6 + 4 = 6.6\, km/h$Converting $6.6$ to a fraction: $6.6 = 6 \frac{6}{10} = 6 \frac{3}{5}\, km/h$.

$A$ car moving in the same direction passes a man walking at $4\, km/h$. The man can see the car for $3\, minutes$ and the visibility is up to a distance of $130\, m$. The speed of the car is: (in $km/h$)

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