A car of mass 1000 kg accelerates uniformly | vedclass

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Question

(B) Given: Mass $m = 1000 \ kg$,initial velocity $u = 0$,final velocity $v = 54 \ km/h = 54 	imes \frac{5}{18} \ m/s = 15 \ m/s$,time $t = 5 \ s$.Ave

Vedclass · Accepted Answer

$22500$

Vedclass · Answer

(B) Given: Mass $m = 1000 \ kg$,initial velocity $u = 0$,final velocity $v = 54 \ km/h = 54 	imes \frac{5}{18} \ m/s = 15 \ m/s$,time $t = 5 \ s$.Average power is defined as the rate of work done,which is equal to the change in kinetic energy divided by time.$P_{avg} = \frac{\Delta K.E.}{t} = \frac{\frac{1}{2}mv^2 - 0}{t}$.Substituting the values: $P_{avg} = \frac{0.5 	imes 1000 	imes (15)^2}{5}$.$P_{avg} = \frac{500 	imes 225}{5} = 100 	imes 225 = 22500 \ W$.

$A$ car of mass $1000 \ kg$ accelerates uniformly from rest to a velocity of $54 \ km/h$ in $5 \ s$. The average power of the engine during this period in watts is .............. $W$ (neglect friction).

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