A car of mass 2000 kg is lifted by a crane t | vedclass

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(B) Given: Mass $M = 2000 \ kg$,Height $h = 30 \ m$,Time $t_1 = 60 \ s$,Time $t_2 = 120 \ s$,Acceleration due to gravity $g = 9.8 \ m/s^2$.The work do

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$9800 \ W, 4900 \ W$

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(B) Given: Mass $M = 2000 \ kg$,Height $h = 30 \ m$,Time $t_1 = 60 \ s$,Time $t_2 = 120 \ s$,Acceleration due to gravity $g = 9.8 \ m/s^2$.The work done $W$ to lift the car is equal to the change in potential energy: $W = Mgh$.$W = 2000 	imes 9.8 	imes 30 = 588,000 \ J = 5.88 	imes 10^5 \ J$.Power $P$ is defined as the rate of doing work: $P = W/t$.For the first crane: $P_1 = W / t_1 = (5.88 	imes 10^5) / 60 = 9800 \ W$.For the second crane: $P_2 = W / t_2 = (5.88 	imes 10^5) / 120 = 4900 \ W$.Thus,the power supplied by the cranes is $9800 \ W$ and $4900 \ W$ respectively.

$A$ car of mass $2000 \ kg$ is lifted by a crane through a distance of $30 \ m$ in $1 \ minute$. $A$ second crane does the same in $2 \ minutes$. The power supplied by each crane is respectively:

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