A car starts from rest and moves with uniform | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The motion can be represented by a velocity-time graph which is a triangle with base $2T$ and height $v_m$.For the first part ($t=0$ to $t=T$),the

Vedclass · Accepted Answer

$\frac{aT}{2}$

Vedclass · Answer

(C) The motion can be represented by a velocity-time graph which is a triangle with base $2T$ and height $v_m$.For the first part ($t=0$ to $t=T$),the car starts from rest with acceleration $a$. The maximum velocity reached is $v_m = aT$.The total distance $s$ traveled is equal to the area under the velocity-time graph.$s = 	ext{Area of triangle} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height} = \frac{1}{2} 	imes (2T) 	imes v_m = T 	imes v_m$.Substituting $v_m = aT$,we get $s = T(aT) = aT^2$.The total time taken is $t_{total} = 2T$.The average speed is given by $v_{avg} = \frac{	ext{total distance}}{	ext{total time}} = \frac{aT^2}{2T} = \frac{aT}{2}$.

$A$ car starts from rest and moves with uniform acceleration $a$ on a straight road from time $t = 0$ to $t = T$. After that,a constant deceleration $a$ brings it to rest. In this process,the average speed of the car is

Similar Questions

The slope of the velocity-time graph for motion with uniform velocity is equal to:

$A$ steel ball is released from rest a distance above a rigid horizontal surface and bounces several times. The diagram shows how its velocity varies with time. Which statement correctly explains why the areas $X$ and $Y$ are equal?

$A$ particle starts from the origin at time $t = 0$ and moves along the positive $x-$ axis. The velocity-time graph is shown in the figure. What is the position of the particle at time $t = 5\,s$ (in $,m$)?

Which of the following curves does not represent motion in one dimension?

The diagram shows the variation of $1/v$ (where $v$ is the velocity of the particle) with respect to time $t$. Using the details given in the graph,the instantaneous acceleration at time $t = 3\,s$ will be equal to $...........\,m/s^2$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module