$A$ carbonyl compound reacts with hydrogen cyanide $(HCN)$ to form cyanohydrin,which on hydrolysis forms a racemic mixture of $\alpha$-hydroxy acid. The carbonyl compound is:
- Aformaldehyde
- Bacetaldehyde
- Cacetone
- Ddiethyl ketone
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Similar Questions
What is the number of different products formed when a mixture of ethanal and propanal reacts with aqueous $NaOH$ after warming?
Cyanohydrin of which compound on hydrolysis will give lactic acid?
In the given reaction,what will be $A$ and $B$ respectively?
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$
Medium
View SolutionMatch the items in List-$I$ with the items in List-$II$ and select the correct code:
List-$I$
List-$II$
$A$. Tollen's reagent
$I$. Para-rosaniline + $SO_2$
$B$. Schiff's reagent
$II$. Rochelle salt + $aq. NaOH$
$C$. Rosenmund reduction
$III$. Ammoniacal silver nitrate
$D$. Fehling solution $B$
$IV$. $Pd + BaSO_4$
| List-$I$ | List-$II$ |
| $A$. Tollen's reagent | $I$. Para-rosaniline + $SO_2$ |
| $B$. Schiff's reagent | $II$. Rochelle salt + $aq. NaOH$ |
| $C$. Rosenmund reduction | $III$. Ammoniacal silver nitrate |
| $D$. Fehling solution $B$ | $IV$. $Pd + BaSO_4$ |
An organic compound $A$ has the molecular formula $C_3H_6O$ and it undergoes the iodoform test. When saturated with dilute $HCl$,it gives $B$ with the molecular formula $C_9H_{14}O$. $A$ and $B$ respectively are:
Difficult
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