A card is drawn at random from a well-shuffle | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In a standard pack of $52$ cards,there are $4$ aces.Therefore,the number of cards that are not aces is $52 - 4 = 48$.The probability of drawing a

Vedclass · Accepted Answer

$\frac{12}{13}$

Vedclass · Answer

(A) In a standard pack of $52$ cards,there are $4$ aces.Therefore,the number of cards that are not aces is $52 - 4 = 48$.The probability of drawing a card that is not an ace is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.$	ext{Probability} = \frac{	ext{Number of non-ace cards}}{	ext{Total number of cards}} = \frac{48}{52}$.Simplifying the fraction by dividing both numerator and denominator by $4$,we get $\frac{48 \div 4}{52 \div 4} = \frac{12}{13}$.

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability that the card drawn is not an ace is ..........

Similar Questions

If $P(\overline{D}) = \frac{6}{17}$,then $P(D) = \ldots$

There are $5$ red,$8$ white,and $4$ green balls in a box. $A$ ball is drawn at random from the box. Find the probability that the ball drawn is not green.

If $P(A) - P(\bar{A}) = 0.5,$ then $P(A) =$ .........

Two players,Sangeeta and Reshma,play a tennis match. It is known that the probability of Sangeeta winning the match is $0.62$. What is the probability of Reshma winning the match?

$A$ die is thrown twice. What is the probability that
$(i)$ $5$ will not come up either time?
$(ii)$ $5$ will come up at least once?

Vedclass Test Series

Exam Paper Generator

Online Exam Module