There are $5$ red,$8$ white,and $4$ green balls in a box. $A$ ball is drawn at random from the box. Find the probability that the ball drawn is not green.

If $P(A) : P(\bar{A}) = 3 : 2$,then $P(A) = \dots$

$A$ student says that if you throw a die,it will show up $1$ or not $1$. Therefore,the probability of getting $1$ and the probability of getting 'not $1$' each is equal to $\frac{1}{2}$. Is this correct? Give reasons.

Two balanced dice are rolled simultaneously. Then,the probability that the numbers appearing on both the dice are different is ........

There are $5$ white,$7$ red,$4$ black and $2$ blue identical balls in a box. One ball is selected at random from the box. Find the probability that the ball is not blue.

$A$ card is drawn at random from a well-shuffled pack of $52$ cards. The probability that the card drawn is not of Diamonds is ..............