A charge q coulomb moves in a circle at n rev | vedclass

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Question

(A) The current $i$ produced by a charge $q$ moving with frequency $n$ is given by $i = qn$.The magnetic field $B$ at the centre of a circular loop of

Vedclass · Accepted Answer

$\frac{2\pi qn}{r} 	imes 10^{-7} 	ext{ T}$

Vedclass · Answer

(A) The current $i$ produced by a charge $q$ moving with frequency $n$ is given by $i = qn$.The magnetic field $B$ at the centre of a circular loop of radius $r$ carrying current $i$ is given by $B = \frac{\mu_0 i}{2r}$.Substituting $\frac{\mu_0}{4\pi} = 10^{-7} 	ext{ T m/A}$,we have $\mu_0 = 4\pi 	imes 10^{-7}$.Thus,$B = \frac{(4\pi 	imes 10^{-7}) 	imes (qn)}{2r}$.Simplifying the expression,we get $B = \frac{2\pi qn}{r} 	imes 10^{-7} 	ext{ T}$.

$A$ charge $q$ coulomb moves in a circle at $n$ revolutions per second and the radius of the circle is $r$ metre; then the magnetic field at the centre of the circle is

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