A charged particle A with charge q = 2 , C ha | vedclass

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(A) The magnetic field $\vec{B}$ produced by a moving point charge $q$ is given by the Biot-Savart Law for a point charge:$\vec{B} = \frac{\mu_0}{4\pi

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$2.5$

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(A) The magnetic field $\vec{B}$ produced by a moving point charge $q$ is given by the Biot-Savart Law for a point charge:$\vec{B} = \frac{\mu_0}{4\pi} \frac{q(\vec{v} 	imes \vec{r})}{r^3}$The magnitude of the magnetic field is:$B = \frac{\mu_0}{4\pi} \frac{qv \sin 	heta}{r^2}$Given values:$q = 2 \, C$$v = 100 \, m/s$$r = 2 \, m$$	heta = 30^{\circ}$$\frac{\mu_0}{4\pi} = 10^{-7} \, T \cdot m/A$Substituting the values:$B = 10^{-7} 	imes \frac{2 	imes 100 	imes \sin 30^{\circ}}{2^2}$$B = 10^{-7} 	imes \frac{200 	imes 0.5}{4}$$B = 10^{-7} 	imes \frac{100}{4}$$B = 25 	imes 10^{-7} \, T$$B = 2.5 	imes 10^{-6} \, T = 2.5 \, \mu T$

$A$ charged particle $A$ with charge $q = 2 \, C$ has a velocity $v = 100 \, m/s$. When it passes through point $A$ with the velocity in the direction shown in the figure,the strength of the magnetic field at point $B$ due to this moving charge is ....... $\mu T$ $(r = 2 \, m)$.

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