$A$ cheetah can accelerate from rest at the rate of $4 \, m \, s^{-2}$.
$(i)$ What will be the velocity attained by it in $10 \, s$?
$(ii)$ How far will it travel in this duration?

(N/A) Initial velocity,$u = 0 \, m \, s^{-1}$.
Acceleration,$a = 4 \, m \, s^{-2}$.
Time,$t = 10 \, s$.
$(i)$ Using the first equation of motion,$v = u + at$:
$v = 0 + (4 \times 10) = 40 \, m \, s^{-1}$.
Thus,the velocity attained is $40 \, m \, s^{-1}$.
$(ii)$ Using the second equation of motion,$s = ut + \frac{1}{2}at^2$:
$s = (0 \times 10) + \frac{1}{2} \times 4 \times (10)^2$
$s = 0 + 2 \times 100 = 200 \, m$.
Thus,the distance traveled is $200 \, m$.