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(C) The volume of a single cube is given by the formula: $V = 	ext{edge} 	imes 	ext{edge} 	imes 	ext{edge}$.Given the edge length is $3 \, cm$, t

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$405$

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(C) The volume of a single cube is given by the formula: $V = 	ext{edge} 	imes 	ext{edge} 	imes 	ext{edge}$.Given the edge length is $3 \, cm$, the volume of one cube is $3 \, cm 	imes 3 \, cm 	imes 3 \, cm = 27 \, cm^3$.By observing the structure in the figure, we can count the total number of cubes:- Column $1$ (leftmost): $5$ cubes- Column $2$: $4$ cubes- Column $3$: $3$ cubes- Column $4$: $2$ cubes- Column $5$ (rightmost): $1$ cubeTotal number of cubes $= 5 + 4 + 3 + 2 + 1 = 15$ cubes.The total volume of the structure is the number of cubes multiplied by the volume of one cube:Total Volume $= 15 	imes 27 \, cm^3 = 405 \, cm^3$.

$A$ child is playing with building blocks, which are in the shape of cubes, and has built a structure as shown in the figure. If the edge of each cube is $3 \, cm$, find the volume of the structure built by the child. (in $cm^3$)

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