A circular wire of radius 7,cm is cut and ben | vedclass

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(B) The circumference of the circular wire is the length of the wire.Given radius $r_1 = 7\,cm$.Length of the wire $L = 2\pi r_1 = 2 	imes \pi 	imes

Vedclass · Accepted Answer

$210$

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(B) The circumference of the circular wire is the length of the wire.Given radius $r_1 = 7\,cm$.Length of the wire $L = 2\pi r_1 = 2 	imes \pi 	imes 7 = 14\pi\,cm$.This wire is now bent into an arc of a circle with radius $r_2 = 12\,cm$.The length of the arc $s = L = 14\pi\,cm$.The formula for the angle $	heta$ subtended by an arc at the center is $	heta = \frac{s}{r_2}$ (in radians).$	heta = \frac{14\pi}{12} = \frac{7\pi}{6}$ radians.To convert radians to degrees,multiply by $\frac{180^o}{\pi}$.$	heta = \frac{7\pi}{6} 	imes \frac{180^o}{\pi} = 7 	imes 30^o = 210^o$.

$A$ circular wire of radius $7\,cm$ is cut and bent again into an arc of a circle of radius $12\,cm$. The angle subtended by the arc at the centre is ......$^o$

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