A circuit and the signal applied at its input | vedclass

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(D) The circuit is a clamper circuit. The input signal $V_i$ varies between $+2 \ V$ and $-2 \ V$. When $V_i = +2 \ V$,the diode $D$ is forward-biased

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(D) The circuit is a clamper circuit. The input signal $V_i$ varies between $+2 \ V$ and $-2 \ V$. When $V_i = +2 \ V$,the diode $D$ is forward-biased and acts as a short circuit. The capacitor $C$ charges to $2 \ V$ with the plate connected to $P$ being positive. The output voltage $V_0$ becomes $0 \ V$. When $V_i$ drops to $-2 \ V$,the diode $D$ becomes reverse-biased and acts as an open circuit. The capacitor $C$ holds its charge of $2 \ V$. The output voltage $V_0$ is given by $V_0 = V_i - V_C = -2 \ V - 2 \ V = -4 \ V$. Thus,the output waveform oscillates between $0 \ V$ and $-4 \ V$.

$A$ circuit and the signal applied at its input terminal $(V_i)$ are shown in the figure below. Which one of the options correctly describes the output waveform $(V_0)$? (Assume all the devices used are ideal and take $P$ as the reference potential.)

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