A clock is set right at 5, am. The clock lose | vedclass

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(B) The clock is set right at $5\, am$ on the $1^{st}$ day.From $5\, am$ on the $1^{st}$ day to $5\, am$ on the $4^{th}$ day is $3 	imes 24 = 72$ hou

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$11\, pm$

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(B) The clock is set right at $5\, am$ on the $1^{st}$ day.From $5\, am$ on the $1^{st}$ day to $5\, am$ on the $4^{th}$ day is $3 	imes 24 = 72$ hours.From $5\, am$ to $10\, pm$ on the $4^{th}$ day is $17$ hours.Total time elapsed according to the faulty clock $= 72 + 17 = 89$ hours.In $24$ hours,the clock loses $16$ minutes,meaning it shows $23$ hours $44$ minutes ($23\frac{11}{15} = \frac{356}{15}$ hours) for every $24$ hours of the correct clock.So,$\frac{356}{15}$ hours of the faulty clock $= 24$ hours of the correct clock.Therefore,$89$ hours of the faulty clock $= (24 	imes \frac{15}{356} 	imes 89)$ hours of the correct clock.$= (24 	imes \frac{15}{356} 	imes 89) = 90$ hours of the correct clock.$90$ hours is equal to $3$ days and $18$ hours.Starting from $5\, am$ on the $1^{st}$ day,$3$ days later is $5\, am$ on the $4^{th}$ day.Adding $18$ hours to $5\, am$ gives $11\, pm$ on the $4^{th}$ day.

$A$ clock is set right at $5\, am.$ The clock loses $16\, minutes$ in $24\, hours.$ What will be the true time when the clock indicates $10\, pm$ on the $4^{th}$ day?

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