A coil with 10 turns and a resistance of 20,O | vedclass

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(C) Given: Number of turns $n = 10$, resistance of coil $R_{	ext{coil}} = 20\,\Omega$, resistance of $B$.$G$. $R_G = 30\,\Omega$.Total resistance in

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(C) Given: Number of turns $n = 10$, resistance of coil $R_{	ext{coil}} = 20\,\Omega$, resistance of $B$.$G$. $R_G = 30\,\Omega$.Total resistance in the circuit $R = R_{	ext{coil}} + R_G = 20 + 30 = 50\,\Omega$.Area of the coil $A = 10^{-2}\,m^2$, magnetic field $B = 10^{-2}\,T$.Initial angle between the area vector and the magnetic field $	heta_1 = 0^{\circ}$.Final angle between the area vector and the magnetic field $	heta_2 = 60^{\circ}$.The induced charge $q$ is given by $q = \frac{\Delta \phi}{R} = \frac{nAB(\cos 	heta_1 - \cos 	heta_2)}{R}$.Substituting the values: $q = \frac{10 	imes 10^{-2} 	imes 10^{-2} 	imes (\cos 0^{\circ} - \cos 60^{\circ})}{50}$.$q = \frac{10^{-3} 	imes (1 - 0.5)}{50} = \frac{10^{-3} 	imes 0.5}{50} = \frac{0.5 	imes 10^{-3}}{50} = 0.01 	imes 10^{-3} = 1 	imes 10^{-5}\,C$.Thus, the charge induced is $1 	imes 10^{-5}\,C$.

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