A coil develops heat of 800 , cal/sec when 20 | vedclass

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(C) The rate of heat production is given by $P = \frac{H}{t} = 800 \, cal/sec$. Converting this to $SI$ units (Joules per second or Watts): $P = 800 \

Vedclass · Accepted Answer

$0.12$

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(C) The rate of heat production is given by $P = \frac{H}{t} = 800 \, cal/sec$. Converting this to $SI$ units (Joules per second or Watts): $P = 800 	imes 4.2 \, J/sec = 3360 \, W$. The formula for electrical power in terms of voltage $V$ and resistance $R$ is $P = \frac{V^2}{R}$. Substituting the given values: $3360 = \frac{20^2}{R}$. $3360 = \frac{400}{R}$. $R = \frac{400}{3360} = \frac{40}{336} \approx 0.119 \, \Omega$. Rounding to two decimal places,we get $R \approx 0.12 \, \Omega$.

$A$ coil develops heat of $800 \, cal/sec$ when $20 \, V$ is applied across its ends. The resistance of the coil is .............. $\Omega$ $(1 \, cal = 4.2 \, J)$.

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