A coin is tossed 3 times. Find the chance tha | vedclass

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(B) The sample space $S$ for tossing a coin $3$ times is given by:$S = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\}$The total number of exhaustive cases

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$\frac{1}{4}$

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(B) The sample space $S$ for tossing a coin $3$ times is given by:$S = \{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\}$The total number of exhaustive cases is $8$.We are looking for outcomes where heads and tails appear alternately. These outcomes are:$HTH$ (Head,Tail,Head)$THT$ (Tail,Head,Tail)Thus,the number of favourable cases is $2$.Therefore,the required probability is $\frac{	ext{Number of favourable cases}}{	ext{Total number of cases}} = \frac{2}{8} = \frac{1}{4}$.

$A$ coin is tossed $3$ times. Find the chance that head and tail show alternately.

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