Two coins are tossed. Let A be the event that | vedclass

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(D) The sample space $S$ for tossing two coins is $S = \{HH, HT, TH, TT\}$.The event $A$ (first coin shows head) is $A = \{HH, HT\}$. Thus,$P(A) = 2/4

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Independent

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(D) The sample space $S$ for tossing two coins is $S = \{HH, HT, TH, TT\}$.The event $A$ (first coin shows head) is $A = \{HH, HT\}$. Thus,$P(A) = 2/4 = 1/2$.The event $B$ (second coin shows tail) is $B = \{HT, TT\}$. Thus,$P(B) = 2/4 = 1/2$.The intersection $A \cap B$ is the event that the first coin shows head $AND$ the second coin shows tail,which is $A \cap B = \{HT\}$.Thus,$P(A \cap B) = 1/4$.Since $P(A) 	imes P(B) = (1/2) 	imes (1/2) = 1/4$,we have $P(A \cap B) = P(A) 	imes P(B)$.Therefore,the events $A$ and $B$ are independent.

Two coins are tossed. Let $A$ be the event that the first coin shows head and $B$ be the event that the second coin shows a tail. The two events $A$ and $B$ are:

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