A compound contains C = 90% and H = 10%. The | vedclass

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(D) To find the empirical formula,we calculate the molar ratio of the elements:            Element      Moles (Percentage / Atomic Mass)      Simplest

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$C_3H_4$

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(D) To find the empirical formula,we calculate the molar ratio of the elements:            Element      Moles (Percentage / Atomic Mass)      Simplest Molar Ratio                  $C$      $90 / 12 = 7.5$      $7.5 / 7.5 = 1$              $H$      $10 / 1 = 10$      $10 / 7.5 = 1.33$      To convert the ratio $1 : 1.33$ into whole numbers,multiply by $3$:$C = 1 	imes 3 = 3$$H = 1.33 	imes 3 = 4$Therefore,the empirical formula is $C_3H_4$.

$A$ compound contains $C = 90\%$ and $H = 10\%$. The empirical formula of the compound is:

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