What is the molecular formula of the alkane,t | vedclass

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Question

(C) At $STP$,$22.4 \, L$ of any gas corresponds to $1 \, mole$.Given that $5.6 \, L$ of the alkane weighs $11 \, g$.Therefore,the mass of $22.4 \, L$

Vedclass · Accepted Answer

$C_3H_8$

Vedclass · Answer

(C) At $STP$,$22.4 \, L$ of any gas corresponds to $1 \, mole$.Given that $5.6 \, L$ of the alkane weighs $11 \, g$.Therefore,the mass of $22.4 \, L$ of the alkane is calculated as:$	ext{Molar mass} = \frac{11 \, g}{5.6 \, L} 	imes 22.4 \, L/mol = 44 \, g/mol$.The general formula for an alkane is $C_nH_{2n+2}$.For $C_nH_{2n+2}$,the molar mass is $12n + 1(2n+2) = 14n + 2$.Setting $14n + 2 = 44$,we get $14n = 42$,so $n = 3$.Thus,the molecular formula is $C_3H_8$.

What is the molecular formula of the alkane,the $5.6 \, L$ of which weighs $11 \, g$ at $STP$?

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