If a compound on analysis was found to contai | vedclass

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Question

(A) To find the empirical formula,we calculate the molar ratio of each element:						Element			Moles (Percentage / Atomic Mass)			Simple Ratio

Vedclass · Accepted Answer

$CHClO$

Vedclass · Answer

(A) To find the empirical formula,we calculate the molar ratio of each element:						Element			Moles (Percentage / Atomic Mass)			Simple Ratio									$C$			$18.5 / 12 = 1.54$			$1.54 / 1.54 = 1$							$H$			$1.55 / 1 = 1.55$			$1.55 / 1.54 \approx 1$							$Cl$			$55.04 / 35.5 = 1.55$			$1.55 / 1.54 \approx 1$							$O$			$24.81 / 16 = 1.55$			$1.55 / 1.54 \approx 1$			The simple ratio of $C:H:Cl:O$ is $1:1:1:1$.Therefore,the empirical formula is $CHClO$.

If a compound on analysis was found to contain $C = 18.5\%$,$H = 1.55\%$,$Cl = 55.04\%$,and $O = 24.81\%$,then its empirical formula is:

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