A compound is treated with NaNH_2 to give a s | vedclass

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(A) $NaNH_2$ is a strong base that can deprotonate terminal alkynes because the acidic hydrogen attached to the $sp$-hybridized carbon is sufficiently

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$C_2H_2$

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(A) $NaNH_2$ is a strong base that can deprotonate terminal alkynes because the acidic hydrogen attached to the $sp$-hybridized carbon is sufficiently acidic.$CH \equiv CH + NaNH_2 	o CH \equiv C^{-} Na^{+} + NH_3$Among the given options,$C_2H_2$ (acetylene) is a terminal alkyne,while $C_6H_6$ (benzene),$C_2H_6$ (ethane),and $C_2H_4$ (ethene) do not have sufficiently acidic protons to react with $NaNH_2$ to form a sodium salt.

$A$ compound is treated with $NaNH_2$ to give a sodium salt. Identify the compound.

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