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(A) Let the distance of the flower from the mirror be $u$. Since the image is formed on a wall,the image is real,so the magnification $m = -16$.By def

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$8$

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(A) Let the distance of the flower from the mirror be $u$. Since the image is formed on a wall,the image is real,so the magnification $m = -16$.By definition,magnification $m = -\frac{v}{u}$. Thus,$-\frac{v}{u} = -16$,which gives $v = 16u$.The distance between the object (flower) and the image (wall) is given as $120 \ cm$. Since the image is real and formed by a concave mirror,the image is formed on the same side as the object. The distance between them is $|v - u| = 120$.Substituting $v = 16u$,we get $|16u - u| = 120$,which simplifies to $15u = 120$.Therefore,$u = \frac{120}{15} = 8 \ cm$.

$A$ concave mirror is used to focus the image of a flower on a nearby wall $120 \ cm$ from the flower. If a lateral magnification of $16$ is desired,the distance of the flower from the mirror should be $... \ cm$.

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