(D) For a conducting sphere,the charge resides on the surface.In the absence of an external electric field,the charge is distributed uniformly over th

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Potential at every point of the sphere must be same.

(D) For a conducting sphere,the charge resides on the surface.In the absence of an external electric field,the charge is distributed uniformly over the surface due to mutual repulsion.However,the property that the entire conductor is an equipotential volume (and thus the surface is an equipotential surface) holds true regardless of the presence of an external electric field.Therefore,the potential at every point on the surface of the conducting sphere must be the same.

Class 12 Physics Electrostatic Potential and Capacitance Equipotential Surface

Medium

$A$ conducting sphere of radius $r$ has a charge. Then

A
The charge is uniformly distributed over its surface,if there is an external electric field.
B
Distribution of charge over its surface will be non-uniform if no external electric field exists in space.
C
Electric field strength inside the sphere will be equal to zero only when no external electric field exists.
D
Potential at every point of the sphere must be same.

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Electrostatic Potential and Capacitance

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Equipotential Surface

The figure shows three points $A, B$ and $C$ in a uniform electric field $(\overrightarrow{E})$. The line $AB$ is perpendicular to $BC$ and $BC$ is parallel to $\overrightarrow{E}$. If $V_A, V_B$ and $V_C$ are the potentials at $A, B$ and $C$ respectively,then the correct option is

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$A$ uniform electric field of magnitude $E = 100 \ V/m$ is directed along the line $y = x + 3$. Find the potential difference $V_A - V_B$ between points $A(3, 1)$ and $B(1, 3)$.

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Two point charges $-Q$ and $+Q / \sqrt{3}$ are placed in the $xy$-plane at the origin $(0,0)$ and a point $(2,0)$,respectively,as shown in the figure. This results in an equipotential circle of radius $R$ and potential $V = 0$ in the $xy$-plane with its center at $(b, 0)$. All lengths are measured in meters.
$(1)$ The value of $R$ is. . . . meter.
$(2)$ The value of $b$ is. . . . . .meter.

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There are two equipotential surfaces as shown in the figure. The distance between them is $r$. If a charge of $-q \text{ C}$ is moved from surface $A$ to surface $B$,the resultant work done will be:

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$A$ circle of radius $R$ is drawn with a charge $+q$ at the centre. $A$ charge $q_0$ is moved from point $B$ to $C$ along the circumference of the circle. The work done is:

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$A$ conducting sphere of radius $r$ has a charge. Then

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The figure shows three points $A, B$ and $C$ in a uniform electric field $(\overrightarrow{E})$. The line $AB$ is perpendicular to $BC$ and $BC$ is parallel to $\overrightarrow{E}$. If $V_A, V_B$ and $V_C$ are the potentials at $A, B$ and $C$ respectively,then the correct option is

$A$ uniform electric field of magnitude $E = 100 \ V/m$ is directed along the line $y = x + 3$. Find the potential difference $V_A - V_B$ between points $A(3, 1)$ and $B(1, 3)$.

There are two equipotential surfaces as shown in the figure. The distance between them is $r$. If a charge of $-q \text{ C}$ is moved from surface $A$ to surface $B$,the resultant work done will be:

$A$ circle of radius $R$ is drawn with a charge $+q$ at the centre. $A$ charge $q_0$ is moved from point $B$ to $C$ along the circumference of the circle. The work done is:

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