A cylinder of 5 L capacity,filled with air a | vedclass

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(C) According to Boyle's law,for a constant temperature,$P_{1}V_{1} = P_{2}V_{2}$.Given:Initial pressure at $N.T.P.$,$P_{1} = 76 \ cm$ of $Hg$.Initial

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(C) According to Boyle's law,for a constant temperature,$P_{1}V_{1} = P_{2}V_{2}$.Given:Initial pressure at $N.T.P.$,$P_{1} = 76 \ cm$ of $Hg$.Initial volume,$V_{1} = 5 \ L$.Final volume,$V_{2} = 5 \ L + 30 \ L = 35 \ L$.Applying the formula:$76 	imes 5 = P_{2} 	imes 35$$P_{2} = \frac{76 	imes 5}{35}$$P_{2} = \frac{76}{7} \approx 10.857 \ cm$ of $Hg$.Rounding to two decimal places,the resultant pressure is $10.86 \ cm$ of $Hg$. The closest option is $10.85 \ cm$ of $Hg$.

$A$ cylinder of $5 \ L$ capacity,filled with air at $N.T.P.$,is connected to another evacuated cylinder of $30 \ L$ capacity. The resultant air pressure in both the cylinders will be ...... $cm$ of $Hg$. (in $.85$)

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