(B) The heat supplied is given by $\Delta Q = mc\Delta T$.Substituting the values: $20000 = 1 \times 400 \times \Delta T$.Thus,$\Delta T = \frac{20000

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(B) The heat supplied is given by $\Delta Q = mc\Delta T$.Substituting the values: $20000 = 1 \times 400 \times \Delta T$.Thus,$\Delta T = \frac{20000}{400} = 50\,^oC$.The work done at constant atmospheric pressure is $W = P\Delta V$.Since $\Delta V = V_0 \gamma \Delta T$,we have $W = P V_0 \gamma \Delta T$.The initial volume $V_0 = \frac{m}{\rho} = \frac{1}{9000}\,m^3$.Substituting the values: $W = (10^5) \times (\frac{1}{9000}) \times (9 \times 10^{-5}) \times 50$.$W = 10^5 \times \frac{1}{9 \times 10^3} \times 9 \times 10^{-5} \times 50 = 10^5 \times 10^{-8} \times 50 = 10^{-3} \times 50 = 0.05\,J$.

Class 11 Physics 1 Thermal Properties of Matter: Thermometry, Expansion and Calorimetry Mix Examples-Thermometry, Thermal Expansion and Calorimetry

Difficult

$A$ cylinder of mass $1\,kg$ is given heat of $20000\,J$ at atmospheric pressure. If the initial temperature of the cylinder is $20\,^oC$,then the work done by the cylinder will be .......$J$. (Given: Specific heat of cylinder $= 400\,J\,kg^{-1}\,^oC^{-1}$,Coefficient of volume expansion $= 9 \times 10^{-5}\,^oC^{-1}$,Atmospheric pressure $= 10^5\,N/m^2$,and density of cylinder $= 9000\,kg/m^3$)

A
$0.02$
B
$0.05$
C
$0.08$
D
$0.1$

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1 Thermal Properties of Matter: Thermometry, Expansion and Calorimetry

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Mix Examples-Thermometry, Thermal Expansion and Calorimetry

Water falls from a height of $200 \ m$ into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. ($g = 10 \ m/s^2$,specific heat of water $s = 4200 \ J/(kg \ K)$) (in $K$)

MediumJEE MAIN 2025

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$A$ given mass $m$ of a hypothetical solid is supplied with heat continuously at a constant rate and the graph shown in the figure is plotted. If $L_f$ and $L_v$ are latent heats of fusion and vaporization,and $S_l$ and $S_s$ are specific heats of liquid and solid respectively,it can be concluded that:

Medium

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$A$ lead bullet at $27\ ^oC$ just melts when stopped by an obstacle. Assuming that $25\%$ of heat is absorbed by the obstacle,the velocity of the bullet at the time of striking is ....... $m/s$. (Melting point of lead $= 327\ ^oC$,specific heat of lead $= 0.03\ cal/g\ ^oC$,latent heat of fusion of lead $= 6\ cal/g$,and $J = 4.2\ J/cal$)

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$A$ beaker is completely filled with water at $4^{\circ}C$. It will overflow if it is:

Medium

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$M \ kg$ of water at $t^{\circ} C$ is divided into two parts so that one part of mass $m \ kg$ when converted into ice at $0^{\circ} C$ would release enough heat to vaporize the other part. Then $\frac{m}{M}$ is equal to (Specific heat of water $= 1 \ cal \ g^{-1} {}^{\circ} C^{-1}$,Latent heat of fusion of ice $= 80 \ cal \ g^{-1}$,Latent heat of steam $= 540 \ cal \ g^{-1}$)

DifficultAP EAMCET 2016

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Water falls from a height of $200 \ m$ into a pool. Calculate the rise in temperature of the water assuming no heat dissipation from the water in the pool. ($g = 10 \ m/s^2$,specific heat of water $s = 4200 \ J/(kg \ K)$) (in $K$)

$A$ beaker is completely filled with water at $4^{\circ}C$. It will overflow if it is:

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