A fair coin with 1 marked on one face and 6 o | vedclass

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(A) The fair coin has faces marked $1$ and $6$. The fair die has faces marked $1, 2, 3, 4, 5,$ and $6$.When both are tossed,the sample space $S$ consi

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$\frac{1}{12}$

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(A) The fair coin has faces marked $1$ and $6$. The fair die has faces marked $1, 2, 3, 4, 5,$ and $6$.When both are tossed,the sample space $S$ consists of all possible pairs $(c, d)$ where $c \in \{1, 6\}$ and $d \in \{1, 2, 3, 4, 5, 6\}$.$S = \{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)\}$.The total number of outcomes is $n(S) = 12$.Let $B$ be the event that the sum of the numbers is $12$.The only outcome that satisfies this is $(6, 6)$,so $B = \{(6, 6)\}$.The number of favorable outcomes is $n(B) = 1$.Therefore,the probability $P(B) = \frac{n(B)}{n(S)} = \frac{1}{12}$.

$A$ fair coin with $1$ marked on one face and $6$ on the other and a fair die are both tossed. Find the probability that the sum of the numbers that turn up is $12$.

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