A flexible circular loop 20 cm in diameter l | vedclass

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(A) The initial radius of the loop is $r = 10 \ cm = 0.1 \ m$.The initial area of the loop is $A_i = \pi r^2 = \pi (0.1)^2 = 0.01 \pi \ m^2$.The final

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$0.1$

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(A) The initial radius of the loop is $r = 10 \ cm = 0.1 \ m$.The initial area of the loop is $A_i = \pi r^2 = \pi (0.1)^2 = 0.01 \pi \ m^2$.The final area of the loop is $A_f = 0 \ m^2$.The change in magnetic flux is $\Delta \phi = B \cdot \Delta A = B(A_f - A_i) = 1 	imes (0 - 0.01 \pi) = -0.01 \pi \ Wb$.The time taken is $\Delta t = 0.314 \ s$.Using Faraday's law,the magnitude of the average induced emf is $|\varepsilon| = \left| -\frac{\Delta \phi}{\Delta t} ight| = \frac{0.01 \pi}{0.314}$.Since $\pi \approx 3.14$,we have $|\varepsilon| = \frac{0.01 	imes 3.14}{0.314} = \frac{0.0314}{0.314} = 0.1 \ V$.

$A$ flexible circular loop $20 \ cm$ in diameter lies in a magnetic field of magnitude $B = 1 \ T$,directed into the plane of the page as shown. The loop is pulled at the points indicated by the arrows,forming a loop of zero area in $0.314 \ s$. The average emf induced in the loop is.....$V$

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