A food packet is dropped from a helicopter ri | vedclass

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(B) The initial velocity of the food packet is the same as the velocity of the helicopter at the moment it is dropped,which is $u = +4 \, ms^{-1}$ (ta

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$25$

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(B) The initial velocity of the food packet is the same as the velocity of the helicopter at the moment it is dropped,which is $u = +4 \, ms^{-1}$ (taking upward as positive).The acceleration of the packet after being dropped is due to gravity,so $a = -g = -9.8 \, ms^{-2}$.Using the first equation of motion,$v = u + at$:$v = 4 + (-9.8 	imes 3)$$v = 4 - 29.4$$v = -25.4 \, ms^{-1}$.The negative sign indicates that the velocity is directed downwards. The magnitude of the velocity is $25.4 \, ms^{-1}$.

$A$ food packet is dropped from a helicopter rising up with a velocity of $4 \, ms^{-1}$. The velocity of the packet after $3 \, s$ will be ....... $ms^{-1}$. (in $.4$)

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