(A) Given: Force $F = 6 \; N$,mass $m = 1 \; kg$,initial velocity $u = 0 \; m/s$,and final velocity $v = 30 \; m/s$.According to Newton's second law o

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(A) Given: Force $F = 6 \; N$,mass $m = 1 \; kg$,initial velocity $u = 0 \; m/s$,and final velocity $v = 30 \; m/s$.According to Newton's second law of motion,the acceleration $a$ is given by $a = \frac{F}{m} = \frac{6 \; N}{1 \; kg} = 6 \; m/s^2$.Using the first equation of motion,$v = u + at$,we can find the time $t$:$30 = 0 + 6 \times t$$t = \frac{30}{6} = 5 \; s$.Therefore,the force acts on the body for $5 \; seconds$.

Class 11 Physics Laws of Motion Second Law of Motion

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$A$ force of $6 \; N$ acts on a body at rest and of mass $1 \; kg$. During this time,the body attains a velocity of $30 \; m/s$. The time for which the force acts on the body is ..... $seconds$.

AIPMT 1997 All AIPMT

A
$5$
B
$7$
C
$8$
D
$10$

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$A$ force of $6 \; N$ acts on a body at rest and of mass $1 \; kg$. During this time,the body attains a velocity of $30 \; m/s$. The time for which the force acts on the body is ..... $seconds$.

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The momentum $p$ (in $kg \cdot m/s$) of a particle is varying with time $t$ (in $s$) as $p = 2 + 3t^2$. The force acting on the particle at $t = 3 \, s$ will be ......... $N$.

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