Class 12PhysicsMoving Charges and MagnetismThe Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion
Medium$A$ galvanometer having a resistance $G$ and current $I_g$ flowing in it,produces full-scale deflection. If $S_1$ is the value of the shunt which converts it into an ammeter of range $0-I$ and $S_2$ is the value of the shunt for range $0-8I$,then the ratio $\frac{S_1}{S_2}$ will be:
- A$\frac{8I - I_g}{I - I_g}$
- B$1$
- C$8$
- D$\frac{1}{2} \left( \frac{I - I_g}{8I - I_g} \right)$
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Similar Questions
To find the resistance of a galvanometer by the half-deflection method,the experimental data obtained are given in the table below:
$S. No.$ Resistance $R \ (\Omega)$ Deflection $(\theta)$ Shunt $S \ (\Omega)$ Half deflection $(\theta / 2)$ Galvanometer resistance $(G)$ $1$ $3300$ $30$ $80$ $15$ $G_1$ $2$ $5000$ $20$ $80$ $10$ $G_2$
From the above data,the galvanometer resistance $G$ will be near to: (in $\Omega$)
| $S. No.$ | Resistance $R \ (\Omega)$ | Deflection $(\theta)$ | Shunt $S \ (\Omega)$ | Half deflection $(\theta / 2)$ | Galvanometer resistance $(G)$ |
| $1$ | $3300$ | $30$ | $80$ | $15$ | $G_1$ |
| $2$ | $5000$ | $20$ | $80$ | $10$ | $G_2$ |
From the above data,the galvanometer resistance $G$ will be near to: (in $\Omega$)
Difficult
View SolutionThe relation between voltage sensitivity $({\sigma _V})$ and current sensitivity $({\sigma _i})$ of a moving coil galvanometer is (Resistance of Galvanometer = $G$)
Easy
View Solution$A$ galvanometer of resistance '$G$' is shunted by a resistance of '$S$' ohm. To keep the main current in the circuit unchanged,the resistance to be put in series with the galvanometer is:
DifficultMHT CET 2024
View SolutionAssertion: Voltmeter is connected in parallel with the circuit.
Reason: Resistance of a voltmeter is very large.
Reason: Resistance of a voltmeter is very large.
$A$ galvanometer with $50$ divisions on the scale has a resistance of $25 \Omega$. $A$ current of $2 \times 10^{-4} \text{ A}$ gives a deflection of one scale division. The additional series resistance required to convert it into a voltmeter reading up to $25 \text{ V}$ is $.... \Omega$.
Medium
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