A galvanometer has a resistance of 100 , Omeg | vedclass

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(B) galvanometer of resistance $G = 100 \, \Omega$ and full-scale current $I_g = 50 \, \mu A = 50 	imes 10^{-6} \, A$ can be used as a voltmeter of r

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$10 \, V$ range with $200 \, k\Omega$ resistance in series

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(B) galvanometer of resistance $G = 100 \, \Omega$ and full-scale current $I_g = 50 \, \mu A = 50 	imes 10^{-6} \, A$ can be used as a voltmeter of range $V$ if a high resistance $R$ is connected in series,where $R = \frac{V}{I_g} - G$.For option $B$ $(V = 10 \, V)$:$R = \frac{10}{50 	imes 10^{-6}} - 100 = 200,000 - 100 = 199,900 \, \Omega \approx 200 \, k\Omega$.Thus,option $B$ is correct.$A$ galvanometer can be converted into an ammeter of range $I$ if a small shunt resistance $S$ is connected in parallel,where $S = \frac{I_g}{I - I_g} 	imes G$.For option $C$ $(I = 5 \, mA = 5 	imes 10^{-3} \, A)$:$S = \frac{50 	imes 10^{-6}}{5 	imes 10^{-3} - 50 	imes 10^{-6}} 	imes 100 \approx \frac{50 	imes 10^{-6}}{5 	imes 10^{-3}} 	imes 100 = 1 \, \Omega$.Since $1 \, \Omega 
eq 10 \, \Omega$,option $C$ is incorrect.For option $D$ $(I = 5 \, mA)$:Since $S \approx 1 \, \Omega 
eq 0.1 \, \Omega$,option $D$ is incorrect.

$A$ galvanometer has a resistance of $100 \, \Omega$ and a full-scale range of $50 \, \mu A$. It can be used as a voltmeter or as a high-range ammeter provided a resistance is added to it. Pick the correct range and resistance combination.

Similar Questions

$A$ galvanometer of resistance $50 \ \Omega$ giving full scale deflection for a current of $10 \ mA$ is to be changed into a voltmeter of range $100 \ V$. $A$ resistance of . . . . . . $\Omega$ has to be connected in series with the galvanometer.

$A$ galvanometer coil has a resistance of $10 \ \Omega$ and the meter shows full-scale deflection for $3 \ \text{mA}$. The value of the shunt required to convert this meter into an ammeter of range $0$ to $10 \ \text{A}$ is . . . . . . $\Omega$.

The deflection in a moving coil galvanometer falls from $50$ divisions to $10$ divisions,when a shunt of $12 \Omega$ is connected with it. The resistance of the galvanometer coil is . . . . . . . (in $\Omega$)

What is the current sensitivity of a galvanometer? How can it be increased?

Assertion: To convert a galvanometer into an ammeter,a small resistance is connected in parallel with it.
Reason: The small resistance increases the combined resistance of the combination.

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