The deflection in a moving coil galvanometer | vedclass

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(B) The deflection $	heta$ in a galvanometer is proportional to the current $I$ flowing through it,so $	heta \propto I$.Initially,the current is $I$

Vedclass · Accepted Answer

$48$

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(B) The deflection $	heta$ in a galvanometer is proportional to the current $I$ flowing through it,so $	heta \propto I$.Initially,the current is $I$ and the deflection is $	heta_1 = 50$ divisions.When a shunt resistance $S$ is connected in parallel,the current $I$ divides such that the galvanometer current $I_g$ corresponds to the new deflection $	heta_2 = 10$ divisions.The ratio of the deflections is $n = \frac{	heta_1}{	heta_2} = \frac{50}{10} = 5$.The formula relating the shunt resistance $S$,galvanometer resistance $G$,and the ratio $n$ is $S = \frac{G}{n-1}$.Rearranging for $G$,we get $G = S(n-1)$.Substituting the given values $S = 12 \Omega$ and $n = 5$:$G = 12 	imes (5 - 1) = 12 	imes 4 = 48 \Omega$.Thus,the resistance of the galvanometer coil is $48 \Omega$.

The deflection in a moving coil galvanometer falls from $50$ divisions to $10$ divisions,when a shunt of $12 \Omega$ is connected with it. The resistance of the galvanometer coil is . . . . . . . (in $\Omega$)

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