A gas at 27^circ C temperature and 30 atmosph | vedclass

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(D) Given:Initial temperature $T_1 = 27^\circ C = 27 + 273 = 300 \ K$.Initial pressure $P_1 = 30 \ atm$.Final pressure $P_2 = 1 \ atm$.Initial volume

Vedclass · Accepted Answer

$-173$

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(D) Given:Initial temperature $T_1 = 27^\circ C = 27 + 273 = 300 \ K$.Initial pressure $P_1 = 30 \ atm$.Final pressure $P_2 = 1 \ atm$.Initial volume $V_1 = V$.Final volume $V_2 = 10V$.Using the ideal gas law equation $\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}$:$T_2 = \frac{P_2 V_2}{P_1 V_1} 	imes T_1$$T_2 = \frac{1 \ atm 	imes 10V}{30 \ atm 	imes V} 	imes 300 \ K$$T_2 = \frac{1}{3} 	imes 300 \ K = 100 \ K$.Converting to Celsius: $T_2(^\circ C) = 100 - 273 = -173^\circ C$.

$A$ gas at $27^\circ C$ temperature and $30$ atmospheric pressure is allowed to expand to atmospheric pressure. If the volume becomes $10$ times its initial volume,then the final temperature becomes ...... $^\circ C$.

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