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(A) According to the first law of thermodynamics,the change in internal energy $\Delta U$ is given by $\Delta U = Q - W$,where $Q$ is the heat supplie

Vedclass · Accepted Answer

$40$

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(A) According to the first law of thermodynamics,the change in internal energy $\Delta U$ is given by $\Delta U = Q - W$,where $Q$ is the heat supplied to the system and $W$ is the work done by the system.Since the initial state $A$ and final state $B$ are the same for both paths $ACB$ and $ADB$,the change in internal energy $\Delta U$ must be the same for both processes.For path $ACB$:$Q_{ACB} = 60 \, J$$W_{ACB} = 30 \, J$$\Delta U = Q_{ACB} - W_{ACB} = 60 - 30 = 30 \, J$For path $ADB$:$W_{ADB} = 10 \, J$Since $\Delta U$ is the same,$\Delta U = Q_{ADB} - W_{ADB}$$30 = Q_{ADB} - 10$$Q_{ADB} = 30 + 10 = 40 \, J$Thus,the heat flow into the system in path $ADB$ is $40 \, J$.

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