A gene locus has two alleles A and a. If the | vedclass

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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of allele $A$ and $q$ is the fre

Vedclass · Accepted Answer

$0.16(AA); 0.48(Aa); 0.36(aa)$

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(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of allele $A$ and $q$ is the frequency of allele $a$.Given $p = 0.4$,then $q = 1 - 0.4 = 0.6$.The genotype frequencies are given by the expansion of $(p + q)^2 = p^2 + 2pq + q^2 = 1$.Here,$p^2$ represents the frequency of homozygous dominant individuals $(AA)$,$2pq$ represents the frequency of heterozygous individuals $(Aa)$,and $q^2$ represents the frequency of homozygous recessive individuals $(aa)$.Calculating the values:$p^2 = (0.4)^2 = 0.16 (AA)$$2pq = 2 	imes 0.4 	imes 0.6 = 0.48 (Aa)$$q^2 = (0.6)^2 = 0.36 (aa)$Therefore,the frequencies are $0.16(AA), 0.48(Aa),$ and $0.36(aa)$.

Genotypes	$BB$	$Bb$	$bb$
Frequency	$22\%$	$62\%$	$16\%$

$A$ gene locus has two alleles $A$ and $a$. If the frequency of the dominant allele $A$ is $0.4$,then what will be the frequency of homozygous dominant,heterozygous,and homozygous recessive individuals in the population?

Similar Questions

If mating is random,the population is large,and mutation does not occur,then the gene frequencies of the population from generation to generation remain constant. This principle was proposed by:

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Frequency $22\%$ $62\%$ $16\%$

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Frequency of heterozygous gene in Hardy-Weinberg principle is represented by . . . . . . .

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