$A$ golf ball has a mass of $40 \, g$ and a speed of $45 \, m/s$. If the speed can be measured within an accuracy of $2 \%$,calculate the uncertainty in the position.

The uncertainty in the speed $(\Delta v)$ is $2 \%$ of $45 \, m/s$:
$\Delta v = 45 \times \frac{2}{100} = 0.9 \, m/s$
Using Heisenberg's uncertainty principle formula:
$\Delta x \times \Delta v = \frac{h}{4 \pi m}$
$\Delta x = \frac{h}{4 \pi m \Delta v}$
Substituting the values ($h = 6.626 \times 10^{-34} \, J \cdot s$,$m = 40 \times 10^{-3} \, kg$,$\Delta v = 0.9 \, m/s$):
$\Delta x = \frac{6.626 \times 10^{-34}}{4 \times 3.14159 \times (40 \times 10^{-3}) \times 0.9}$
$\Delta x = \frac{6.626 \times 10^{-34}}{0.45239} \approx 1.46 \times 10^{-33} \, m$
This value is extremely small,indicating that the uncertainty principle is insignificant for macroscopic objects like a golf ball.