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(B) Let the mass of the light particle be $m_1$ and the mass of the heavy block be $m_2$. Since the block is very heavy,$m_2 \gg m_1$.For a one-dimens

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Move at $8\ m/s$ in its original direction

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(B) Let the mass of the light particle be $m_1$ and the mass of the heavy block be $m_2$. Since the block is very heavy,$m_2 \gg m_1$.For a one-dimensional elastic collision,the velocity of the first particle after collision $v_1'$ is given by:$v_1' = \frac{m_1 - m_2}{m_1 + m_2} v_1 + \frac{2m_2}{m_1 + m_2} v_2$Given $v_1 = 12\ m/s$ and $v_2 = 10\ m/s$. Since $m_2 \gg m_1$,we can approximate $\frac{m_1 - m_2}{m_1 + m_2} \approx -1$ and $\frac{2m_2}{m_1 + m_2} \approx 2$.Substituting these values:$v_1' \approx (-1) 	imes 12 + (2) 	imes 10$$v_1' \approx -12 + 20 = 8\ m/s$.Since the result is positive,the particle moves at $8\ m/s$ in its original direction.

$A$ light particle moving horizontally with a speed of $12\ m/s$ strikes a very heavy block moving in the same direction at $10\ m/s$. The collision is one-dimensional and elastic. After the collision,the particle will

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