A line intersects the y-axis and x-axis at th | vedclass

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(D) Let the coordinates of $P$ be $(0, y)$ and $Q$ be $(x, 0)$,respectively.The mid-point of $P(0, y)$ and $Q(x, 0)$ is given by the formula $\left(\f

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$(0, -10)$ and $(4, 0)$

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(D) Let the coordinates of $P$ be $(0, y)$ and $Q$ be $(x, 0)$,respectively.The mid-point of $P(0, y)$ and $Q(x, 0)$ is given by the formula $\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$.Thus,the mid-point $M$ is $\left(\frac{0+x}{2}, \frac{y+0}{2}\right) = \left(\frac{x}{2}, \frac{y}{2}\right)$.It is given that the mid-point of $PQ$ is $(2, -5)$.Equating the coordinates,we get:$\frac{x}{2} = 2 \Rightarrow x = 4$$\frac{y}{2} = -5 \Rightarrow y = -10$Therefore,the coordinates of $P$ are $(0, -10)$ and $Q$ are $(4, 0)$.

$A$ line intersects the $y$-axis and $x$-axis at the points $P$ and $Q$,respectively. If $(2, -5)$ is the mid-point of $PQ$,then the coordinates of $P$ and $Q$ are,respectively:

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