A line joining the points (1, 2, 0) and (4, 1 | vedclass

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(B) The direction ratios of the line passing through the points $(x_1, y_1, z_1) = (1, 2, 0)$ and $(x_2, y_2, z_2) = (4, 13, 5)$ are given by $(x_2 -

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$3, 11, 5$

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(B) The direction ratios of the line passing through the points $(x_1, y_1, z_1) = (1, 2, 0)$ and $(x_2, y_2, z_2) = (4, 13, 5)$ are given by $(x_2 - x_1, y_2 - y_1, z_2 - z_1)$.Substituting the values,we get $(4 - 1, 13 - 2, 5 - 0) = (3, 11, 5)$.Since the line is perpendicular to the plane,the direction ratios of the line are the same as the direction ratios of the normal to the plane.The equation of a plane with normal vector $(a, b, c)$ is $ax + by + cz + d = 0$.Therefore,the coefficients of $x, y$ and $z$ in the equation of the plane are the direction ratios of the normal,which are $3, 11, 5$.

$A$ line joining the points $(1, 2, 0)$ and $(4, 13, 5)$ is perpendicular to a plane. Then the coefficients of $x, y$ and $z$ in the equation of the plane are respectively

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