A liquid is coming out from a vertical tube. | vedclass

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Question

(B) When a liquid drop is about to detach from a vertical tube,the weight of the drop $W$ is balanced by the upward force due to surface tension actin

Vedclass · Accepted Answer

$W = 2\pi r T$

Vedclass · Answer

(B) When a liquid drop is about to detach from a vertical tube,the weight of the drop $W$ is balanced by the upward force due to surface tension acting along the circumference of the tube.The force due to surface tension $F$ is given by $F = T 	imes 	ext{circumference} = T 	imes (2\pi r)$.Since the angle of contact is zero,the force acts vertically upwards along the tube wall.At the point of detachment,the weight of the drop $W$ is equal to this surface tension force.Therefore,$W = 2\pi r T$.

$A$ liquid is coming out from a vertical tube. The relation between the weight of the drop $W$,surface tension of the liquid $T$,and radius of the tube $r$ is given by,if the angle of contact is zero.

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