A long solenoid with 20 turns per cm is made. | vedclass

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(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n i$.Here, $n$ is the number of turns per unit length.Given: $n =

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$8$

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(A) The magnetic field $B$ inside a long solenoid is given by the formula $B = \mu_0 n i$.Here, $n$ is the number of turns per unit length.Given: $n = 20 	ext{ turns/cm} = 2000 	ext{ turns/m}$.Given: $B = 20 	ext{ mT} = 20 	imes 10^{-3} 	ext{ T}$.Given: $\mu_0 = 4\pi 	imes 10^{-7} 	ext{ T} \cdot 	ext{m/A}$.Substituting the values into the formula:$20 	imes 10^{-3} = (4\pi 	imes 10^{-7}) 	imes 2000 	imes i$$20 	imes 10^{-3} = 8\pi 	imes 10^{-4} 	imes i$$i = \frac{20 	imes 10^{-3}}{8\pi 	imes 10^{-4}} = \frac{200}{8\pi} = \frac{25}{\pi} \approx \frac{25}{3.14} \approx 7.96 	ext{ A}$.Rounding to the nearest integer, the current is approximately $8 	ext{ A}$.

$A$ long solenoid with $20$ turns per $cm$ is made. To produce a magnetic field of $20$ $mT$ inside the solenoid, the necessary current will be approximately......$A$.

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