A long straight wire carries a current of pi | vedclass

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Question

(A) The magnetic field $B$ at a distance $r$ from a long straight wire carrying current $i$ is given by the formula: $B = \frac{\mu_0 i}{2\pi r}$.Give

Vedclass · Accepted Answer

$10^4 \mu_0 \, m$

Vedclass · Answer

(A) The magnetic field $B$ at a distance $r$ from a long straight wire carrying current $i$ is given by the formula: $B = \frac{\mu_0 i}{2\pi r}$.Given: $i = \pi \, A$,$B = 5 	imes 10^{-5} \, Wb/m^2$.Substituting the values into the formula:$5 	imes 10^{-5} = \frac{\mu_0 	imes \pi}{2\pi r}$.Simplifying the expression:$5 	imes 10^{-5} = \frac{\mu_0}{2r}$.Solving for $r$:$r = \frac{\mu_0}{2 	imes 5 	imes 10^{-5}} = \frac{\mu_0}{10 	imes 10^{-5}} = \frac{\mu_0}{10^{-4}} = 10^4 \mu_0 \, m$.

$A$ long straight wire carries a current of $\pi \, A$. The magnetic field due to it will be $5 \times 10^{-5} \, Wb/m^2$ at what distance from the wire? $[\mu_0 = \text{permeability of free space}]$

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