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(D) Let $T$ be the tension in the rope. The force $T$ acts on both the man and the block.Since the block is heavier than the man $(M_{block} > M_{man}

Vedclass · Accepted Answer

All of the above.

Vedclass · Answer

(D) Let $T$ be the tension in the rope. The force $T$ acts on both the man and the block.Since the block is heavier than the man $(M_{block} > M_{man})$ and the coefficient of friction $\mu$ is the same for both,the limiting friction force $f_L = \mu N = \mu Mg$ is greater for the block than for the man $(f_{L, block} > f_{L, man})$.Each body will start moving when the tension $T$ exceeds its respective limiting friction.$1$. When $T$ exceeds $f_{L, man}$ but is less than $f_{L, block}$,the man will start moving,but the block will remain stationary. Thus,option $B$ is correct.$2$. Since the block requires a larger force to move,it will not move unless the man exerts enough force,which implies the man must be in a state of motion or exerting force that overcomes the block's friction. Thus,option $A$ is correct.$3$. If both move,the net force on the man is $F_{net, man} = T - f_{k, man}$ and on the block is $F_{net, block} = T - f_{k, block}$. Since $f_{k, block} > f_{k, man}$,the net force on the man is greater. Given $M_{man} Therefore,all statements are correct.

$A$ man pulls a block heavier than himself with a light horizontal rope. The coefficient of friction is the same between the man and the ground,and between the block and the ground.

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