A metal pipe is 77 , cm long. The inner diame | vedclass

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(B) Given:Length of the pipe $(h)$ = $77 \, cm$Inner diameter $(d_1)$ = $4 \, cm$,so inner radius $(r_1)$ = $2 \, cm$Outer diameter $(d_2)$ = $4.4 \,

Vedclass · Accepted Answer

$2038.08$

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(B) Given:Length of the pipe $(h)$ = $77 \, cm$Inner diameter $(d_1)$ = $4 \, cm$,so inner radius $(r_1)$ = $2 \, cm$Outer diameter $(d_2)$ = $4.4 \, cm$,so outer radius $(r_2)$ = $2.2 \, cm$Total surface area of the pipe = (Inner curved surface area) + (Outer curved surface area) + (Area of two circular rings at the ends)Inner curved surface area = $2 \pi r_1 h = 2 	imes \frac{22}{7} 	imes 2 	imes 77 = 2 	imes 22 	imes 2 	imes 11 = 968 \, cm^2$Outer curved surface area = $2 \pi r_2 h = 2 	imes \frac{22}{7} 	imes 2.2 	imes 77 = 2 	imes 22 	imes 2.2 	imes 11 = 1064.8 \, cm^2$Area of two circular rings = $2 	imes \pi (r_2^2 - r_1^2) = 2 	imes \frac{22}{7} 	imes (2.2^2 - 2^2) = 2 	imes \frac{22}{7} 	imes (4.84 - 4) = 2 	imes \frac{22}{7} 	imes 0.84 = 2 	imes 22 	imes 0.12 = 5.28 \, cm^2$Total surface area = $968 + 1064.8 + 5.28 = 2038.08 \, cm^2$.

$A$ metal pipe is $77 \, cm$ long. The inner diameter of a cross section is $4 \, cm$ and the outer diameter is $4.4 \, cm$ (see Fig.). Find its total surface area. (in $, cm^2$)

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