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(B) $v$: speed of electron having maximum kinetic energy.From Einstein's photoelectric equation:$E = \phi + K.E._{\max}$$\frac{hc}{\lambda} = h 
u_{0

Vedclass · Accepted Answer

$5$

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(B) $v$: speed of electron having maximum kinetic energy.From Einstein's photoelectric equation:$E = \phi + K.E._{\max}$$\frac{hc}{\lambda} = h 
u_{0} + \frac{1}{2} m_{e} v^{2}$$\frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^{8}}{500 	imes 10^{-9}} = 6.63 	imes 10^{-34} 	imes 4.3 	imes 10^{14} + \frac{1}{2} 	imes 9.0 	imes 10^{-31} 	imes v^{2}$$3.978 	imes 10^{-19} = 2.8509 	imes 10^{-19} + 4.5 	imes 10^{-31} 	imes v^{2}$$1.1271 	imes 10^{-19} = 4.5 	imes 10^{-31} 	imes v^{2}$$v^{2} = \frac{1.1271 	imes 10^{-19}}{4.5 	imes 10^{-31}} \approx 0.2504 	imes 10^{12} = 25.04 	imes 10^{10}$$v \approx 5.004 	imes 10^{5} \ ms^{-1}$Rounding to the nearest integer,the value is $5$.

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