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Question

(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$ in the presence of aqueous $NaOH$ is a $Crossed \ Cannizzaro \ reaction$

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Benzyl alcohol and sodium formate

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(A) The reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$ in the presence of aqueous $NaOH$ is a $Crossed \ Cannizzaro \ reaction$.In this reaction,the more reactive aldehyde (formaldehyde) undergoes oxidation to form a formate salt,while the less reactive aldehyde (benzaldehyde) undergoes reduction to form an alcohol.$C_6H_5CHO + HCHO \xrightarrow{NaOH_{(aq)}} C_6H_5CH_2OH + HCOONa$Thus,the products are benzyl alcohol $(C_6H_5CH_2OH)$ and sodium formate $(HCOONa)$.

$A$ mixture of benzaldehyde and formaldehyde on heating with aqueous $NaOH$ solution gives:

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