A monkey of mass 40 ,kg climbs up a rope,of b | vedclass

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(A) The maximum tension the rope can withstand is $T_{max} = 600 \,N$.The weight of the monkey is $W = mg = 40 	imes 10 = 400 \,N$.Applying Newton's

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$2$

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(A) The maximum tension the rope can withstand is $T_{max} = 600 \,N$.The weight of the monkey is $W = mg = 40 	imes 10 = 400 \,N$.Applying Newton's second law for the monkey climbing up with maximum acceleration $a$:$T_{max} - mg = ma$$600 - 400 = 40a$$200 = 40a$$a = 5 \,m/s^2$Using the equation of motion $S = ut + \frac{1}{2}at^2$,where initial velocity $u = 0$,distance $S = 10 \,m$,and $a = 5 \,m/s^2$:$10 = 0 + \frac{1}{2} 	imes 5 	imes t^2$$10 = 2.5 t^2$$t^2 = 4$$t = 2 \,s$Thus,the time taken is $2 \,s$.

$A$ monkey of mass $40 \,kg$ climbs up a rope,of breaking load $600 \,N$ hanging from a ceiling. If it climbs up the rope with the maximum possible acceleration,then the time taken by the monkey to climb up is .........$s$ [Length of rope is $10 \,m$]

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