A nucleus with mass number 240 breaks into tw | vedclass

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(D) The initial nucleus has a mass number $A = 240$ and binding energy per nucleon $BE_{initial} = 7.6 \, MeV$.The total binding energy of the initial

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$216$

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(D) The initial nucleus has a mass number $A = 240$ and binding energy per nucleon $BE_{initial} = 7.6 \, MeV$.The total binding energy of the initial nucleus is $240 	imes 7.6 = 1824 \, MeV$.After the process,the nucleus breaks into two fragments,each with mass number $A = 120$ and binding energy per nucleon $BE_{final} = 8.5 \, MeV$.The total binding energy of the two fragments is $2 	imes (120 	imes 8.5) = 240 	imes 8.5 = 2040 \, MeV$.The gain in binding energy is the difference between the total binding energy of the products and the reactants:$Q = BE_{products} - BE_{reactants} = 2040 \, MeV - 1824 \, MeV = 216 \, MeV$.

$A$ nucleus with mass number $240$ breaks into two fragments each of mass number $120$. The binding energy per nucleon of the unfragmented nucleus is $7.6 \, MeV$,while that of the fragments is $8.5 \, MeV$. The total gain in the binding energy in the process is (in $MeV$):

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