If 200 text{ MeV} of energy is released in th | vedclass

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(A) Energy released in the fission of one nucleus is $E_1 = 200 	ext{ MeV}$.Converting this energy into Joules:$E_1 = 200 	imes 1.6 	imes 10^{-13}

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$3.125 	imes 10^{13}$

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(A) Energy released in the fission of one nucleus is $E_1 = 200 	ext{ MeV}$.Converting this energy into Joules:$E_1 = 200 	imes 1.6 	imes 10^{-13} 	ext{ J} = 3.2 	imes 10^{-11} 	ext{ J}$.We need to find the number of nuclei $(n)$ required to release a total energy $E_{total} = 1000 	ext{ J}$.The relationship is $E_{total} = n 	imes E_1$.Therefore, $n = \frac{E_{total}}{E_1} = \frac{1000}{3.2 	imes 10^{-11}}$.$n = \frac{10^3}{3.2 	imes 10^{-11}} = \frac{1}{3.2} 	imes 10^{14} = 0.3125 	imes 10^{14} = 3.125 	imes 10^{13}$ nuclei.

If $200 \text{ MeV}$ of energy is released in the fission of one nucleus of ${ }_{92}^{236} U$, the number of nuclei that must undergo fission to release an energy of $1000 \text{ J}$ is

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